This is an improvement over a classic riddle. The original riddle goes
like this:
Consider the number 3 0 2 5.
It is this relaxed riddle that we want to consider. The riddle this month is composed of two questions. Answer both to be considered a solver. Question 1:If the relaxed version of the riddle is asked in an arbitrary base, b, instead of in base 10, how many solutions is it going to have, as a function of b?Question 2:Consider the strict (original) version of the riddle, but, once again, asked in base b instead of in base 10. Will there be an answer for every b≥4? Prove your claim. |
List of solvers:Oded Margalit (4 Apr 23:00) Itsik Horovitz (10 Apr 20:46) |
Elegant solutions can be submitted to the puzzlemaster at riddlesbrand.scso.com. Names of solvers will be posted on this page. Notify if you don't want your name to be mentioned.
The solution will be published at the end of the month.
Enjoy!